Question regarding mongodb and typescript. using lean() funciton i have to do this big mess of typescript transformations of if ect. Is there a more straighforward way to get the day withoug this typescript mess, should i not use lean(). here a next js action example below:

'use server';
import {
  CountryDocument,
  CategoryScore,
  Metric,
} from '@/types/CountryDocument';
import connectDB from '@/lib/connectDB';
import Country from '@/models/Country';

export async function fetchCountryData(
  countryName: string
): Promise<CountryDocument> {
  await connectDB();

  try {
    const country = await Country.findOne({
      name: {
        $regex: `^${countryName}$`,
        $options: 'i', // Case-insensitive match
      },
    }).lean<CountryDocument>(); // Explicitly define the expected type

    if (!country) {
      throw new Error('Country not found');
    }

    // Transform MongoDB ObjectId fields to strings
    const transformedCountry: CountryDocument = {
      ...country,
      _id: country._id?.toString(), // Convert _id to string
      categoryScores: country.categoryScores.map((category: CategoryScore) => ({
        ...category,
        _id: category._id?.toString(), // Convert category _id to string
        categoryEmoji: category.categoryEmoji || '', // Default emoji to empty string
        metrics: category.metrics.map((metric: Metric) => ({
          ...metric,
          _id: metric._id?.toString(), // Convert metric _id to string
        })),
      })),
    };
    console.log('Transformed Data:', transformedCountry.categoryScores);


    return transformedCountry;
  } catch (error) {
    console.error('Error fetching country:', error);
    throw new Error('Error fetching country');
  }
}